Sol

规律题，根据 $n*m$ 的奇偶性判断即可

Code

#include<bits×dc++.h>
#define ll long long
using namespace std;
int main(){
	int T;
	cin>>T;
	while(T--){
		string a,b;
		cin>>a>>b;
		char c=a[a.size()-1],d=b[b.size()-1];
		if(int(c-'0')*int(d-'0')%2) cout<<"XYC wins!!!\n";
		else cout<<"WMC wins!!!\n";
	}
	return 0;
}