Let's assume that you have n integers, A₁, A₂, A₃ ... A_n.

Let's define:

• E = Number of pairs (i, j) such that i < j and (A_i + A_j) are even.
• O = Number of pairs (i, j) such that i < j and (A_i + A_j) are odd.
• D = | E-O | (That means, D = (E-O) if (E-O) ≥ 0, -(E-O) otherwise.)

Unfortunately, you do have n but those n integers are lost. You will have to buy them again. Before going to the market, you have decided that you will buy n integers in such a way that the value of D will be as small as possible, as you will have to pay D golden coins to buy them.

Now, you are wondering, what that minimum D will be. (Let's call it D_min).

Input

First line of the input file will contain the number of test cases, T ≤ 1000000, followed by T lines, each containing an integer n (1 ≤ n ≤ 10⁹).

Output

For each case, print the case number starting from 1 and D_min for the value of n in that particular case. See the sample output for exact formatting.

Example

Input:
3
3
4
5
Output:
Case 1: 1
Case 2: 0
Case 3: 2

Warning: Input file is huge, please use faster input and output methods (e.g. printf and scanf in C++).

Problem Setter: Momontho Mashak Monmoy

Special Thanks: Muhammad Ridowan